ZedBull - ID48 Unlock

**DaBotta** · 16th December, 2018, 03:15 AM

Hello friends ,

I have an Mini ZedBull Clone , i had tried with different software to unlock the ID48 Magic II transponder , but no succes. Everytime i recieve error 9

Is there any other way to unlock those ID48 transponders ?

Thank you

**ciprishor** · 16th December, 2018, 11:52 AM

This is possible only if you have the password for the car that locked it or the dump from that bcm/cluster

**jakesman** · 16th December, 2018, 12:09 PM

from personal experiance , not all id48 chip can be unlocked , some will unlock and other not , with zedbull , on older vw 2003 2005 i have unlocked them , but again not all , will unlock , then u can pre-code it again for you vag model , if it is for vag car

**rob h** · 16th December, 2018, 12:11 PM

If the password is known, it will unlock.
Some i unlock with vvdi2, some with Tango.

**DaBotta** · 16th December, 2018, 05:37 PM

I have some keys from park with distroyed cars , so don't know password.

So can't do anything with them ? All of them are ID48 CanBus

**exe123** · 16th December, 2018, 08:47 PM

Originally Posted by DaBotta

So can't do anything with them ? All of them are ID48 CanBus

No, nothing you can do. New id48 are so cheap

**H2Deetoo** · 18th December, 2018, 10:02 AM

If you write some software you can easily brute the right pincode/password.
It will just take some time ...

**DaBotta** · 18th December, 2018, 10:05 AM

What software?

Thank you

Trimis de pe al meu SM-G935F folosind Tapatalk

**exe123** · 18th December, 2018, 11:07 AM

Some times will be very long. Several years for brute force one

**H2Deetoo** · 18th December, 2018, 02:16 PM

No, it is just a 32bit pincode, so can be done pretty quickly.

**exe123** · 18th December, 2018, 02:45 PM

Originally Posted by H2Deetoo

No, it is just a 32bit pincode, so can be done pretty quickly.

00000000 - FFFFFFFF = 4294967295 combinations.
Even if it takes 0,1 seconds per try. We have 4294967295 * 0,1s ~ 4791 days so around 13 years to bruteforce all combinations. Sure if your code is somewhere in the middle, it will take just 6...