Eeprom , to read and write to 8bit or 16 bit...

[Yhoni]

Hello friends, there are some eeprom memories that have the ability to read and write in 8 bit and 16 bit (example: 93c66).

Does anyone know how to know if the reading and writing should be done in 8 bit or in 16 bit when you read an ecu or a cluster, please?

Searching the forum I found this post that deals with this topic:


https://www.digital-kaos.co.uk/forum...n-93C66-Eeprom


From what I have understood:


- Pin 6 linked to pin 5 = 8 bit, read & write
- Pin 6 linked to pin 8 (pin 5 ground) = 16 bit, read & write


Can anyone confirm if this is correct ?.


Thank you.

[eric paris]

Hello,
I often have the same problem so I take the datasheet and I look at the ORG pin how it is wired

for the ST 93C

MEMORY ORGANIZATION
The M93Cx6 memory is organized either as bytes(x8) or as words (x16).
If Organization Select(ORG) is left unconnected (or connected to VCC)the x16 organization is selected;
when Organiza-tion Select (ORG) is connected to Ground (VSS)the x8 organization is selected.
When the M93Cx6is in stand-by mode, Organization Select (ORG)should be set either to VSS or VCC for
minimumpower consumption. Any voltage between VSSand VCC applied to Organization Select (ORG)
may increase the stand-by current


I don't know if this is the right solution but it works for me

[Yhoni]

Hello,
I often have the same problem so I take the datasheet and I look at the ORG pin how it is wired

for the ST 93C

MEMORY ORGANIZATION
The M93Cx6 memory is organized either as bytes(x8) or as words (x16).
If Organization Select(ORG) is left unconnected (or connected to VCC)the x16 organization is selected;
when Organiza-tion Select (ORG) is connected to Ground (VSS)the x8 organization is selected.
When the M93Cx6is in stand-by mode, Organization Select (ORG)should be set either to VSS or VCC for
minimumpower consumption. Any voltage between VSSand VCC applied to Organization Select (ORG)
may increase the stand-by current


I don't know if this is the right solution but it works for me

Ok friend, thanks for to share this information.

leg VCC=1
leg VSS=5 ( ground )
leg ORG=6
leg 8 free

I understand:

- 6 left unconnected =16bit
- 6+1=16bit
- 6+8=16 bit
- 6+5= 8bit

[eric paris]

yes
l look where is the pin vcc and the pin vss ground on the eeprom
after l look where the pin org is connected